Question

Determine as raízes da função x²+8x+16=0

Answer 1

delta = 64 - 4.16 

delta = 0 


x = (8 + 0) / 2 = 4 

***************** 
x' = x" = 4 

Answer 2

$x^{2} +8x+16=0 \\ \\ a=1 \\ b=8 \\ c=16 \\ \\ \Delta=b^2-4ac \\ \Delta=8^2-4(1)(16) \\ \Delta=64-64 \\ \Delta=0 \\ \\ x= \frac{-b\pm \sqrt{\Delta} }{2a} \\ \\ x= \frac{-8\pm0}{2} \\ \\ x'=x"=- \frac{8}{2} =-4 \\ \\ S=\{-4\}$