Question

determine as raizes da função f(x) =x2-22x+5

Answer 1

Boa tarde

x² - 22x + 5 = 0

delta
d² = 484 - 20 = 464 
d = 4√29

x1 = (22 + 4√29)/2 = 11 + 2√29
x2 = (22 - 4v29)/2  = 11 - 2√29 

Answer 2

x²-22x+5
Δ=(-22)²-4(1)(5)
Δ=484-20
Δ=464

x'=$\frac{22+4 \sqrt{29} }{2}$

x"=$\frac{22-4 \sqrt{29} }{2}$