Question

determine as raízes da função f(x)=-x2+12x+20

Answer 1

-x^2+12x+20=0

a=-1

b=12

c=20

∆=b^2-4.a.c

∆=(12)^2-4.(-1).(20)

∆=144+80

∆=224

224/2
112/2
56/2
28/2
14/2
7/7
1

224=2^4.2.7=2^4.14

x'=-12+√224/2.(-1)

x=-12+4√17/-2

x=6-2√14

x2=6+√14

s={6-2√14;6+2√14}

espero ter ajudado!

boa tarde!

Answer 2

∆= 144 +80= 224 => √∆=√16.14= 4√14

x'= -12+4√14/-2= -2(6-2√14)/-2= 6-2√14✓

x'= -12-4√14/-2= -2(6+2√14)/-2=6+2√14✓