determine as raizes da equaçoes
2x²+x-1=0 b)2x²+2x-24=0
Soluções para a tarefa
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a)
2x² + x - 1 = 0
a = 2, b = 1; c = - 1
Δ = b² - 4ac
Δ = 1 - 4.2.(-1)
Δ = 1 + 8
Δ = 9
√Δ = 3
x = - b +/-√Δ
2a
x' = - 1 + 3 = 2 (:2) = 1
2.2 4 (:2) 2
x" = - 1 - 3 = - 4 = - 1
2.2 4
Resp.: x = 1/2 e x = - 1
b)
2x² + 2x - 24 = 0 (:2)
x² + x - 12 = 0
a = 1; b = 1; c = - 12
Δ = b² - 4ac
Δ = 1 - 4.1.(-12)
Δ = 1 + 48
Δ = 49
√Δ = 7
x = - b +/- √Δ
2a
x' = - 1 + 7 = 6/2 = 3
2
x" = - 1 - 7 = - 8/2 = - 4
2
Resp.: x = 3 e x = - 4
2x² + x - 1 = 0
a = 2, b = 1; c = - 1
Δ = b² - 4ac
Δ = 1 - 4.2.(-1)
Δ = 1 + 8
Δ = 9
√Δ = 3
x = - b +/-√Δ
2a
x' = - 1 + 3 = 2 (:2) = 1
2.2 4 (:2) 2
x" = - 1 - 3 = - 4 = - 1
2.2 4
Resp.: x = 1/2 e x = - 1
b)
2x² + 2x - 24 = 0 (:2)
x² + x - 12 = 0
a = 1; b = 1; c = - 12
Δ = b² - 4ac
Δ = 1 - 4.1.(-12)
Δ = 1 + 48
Δ = 49
√Δ = 7
x = - b +/- √Δ
2a
x' = - 1 + 7 = 6/2 = 3
2
x" = - 1 - 7 = - 8/2 = - 4
2
Resp.: x = 3 e x = - 4
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