Question

determine as raízes da equação -x²+x+12=0​

Answer 1

x¹ = 4

x² = -3

$\sf {\Huge ——————— }$

Coeficientes

$\sf \green{ -x^{2} } \red{ + x} \orange{ + 12 = } \purple{ 0 } \\ \sf \pink{x^{2} } \blue{ - x} \green{-12=} \red{0}$

a = 1

b = -1

c = -12

Delta

$\sf \red{\Delta =(- 1)^{2} - 4.1.(-12)} \\ \sf \red{\Delta = 1-4.1.(-12)}\\ \sf \red{\Delta=1-4.(-12)}\\ \sf \red{\Delta=1-(-48)}\\ \sf\red{\Delta =1 + 48}\\ \sf \red{\Delta=49 }$

Bhaskara

$\sf \pink{\frac{-(-1)\pm \sqrt{49}}{2.1}} \\ \sf\pink{\frac{1 \pm 7}{2}}\\ \\ \sf\pink{\frac{1+7}{2} =\frac{8}{2}=4 } \\ \sf \pink{\frac{1-7}{2} =\frac{-6}{2}=-3 }$