Question

determine as raizes da equacao 3x²+7x-26=0

Answer 1

Δ=b²-4ac =7²-4.3.(-26) =49+312= 361

x= -7+√361/2.3

x=-7+19/6

x=12/6

x=2

x=-7-19/6

x=-26/6

x=-13/2

S={2,-13/2}

Answer 2

Δ = 7² - 4 x 3 x (-26)
Δ = 49 - (-312)
Δ = 361

x = -7 +- √361 / 2 x 7
x = -7 +- 19 / 14
x' = 0,85
x'' = -1,85