Question

determine as raízes da equação 2xkç2-3x-5=0

Answer 1

Resposta:

S={-1; 2,5}

Explicação passo-a-passo:

2x²-3x-5=0

$\displaystyle Aplicando~a~f\acute{o}rmula~de~Bhaskara~para~2x^{2}-3x-5=0~~e~comparando~com~(a)x^{2}+(b)x+(c)=0,~determinamos~os~coeficientes:~\\a=2{;}~b=-3~e~c=-5\\\\C\acute{a}lculo~do~discriminante~(\Delta):&\\&~\Delta=(b)^{2}-4(a)(c)=(-3)^{2}-4(2)(-5)=9-(-40)=49\\\\C\acute{a}lculo~das~raizes:&\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-3)-\sqrt{49}}{2(2)}=\frac{3-7}{4}=\frac{-4}{4}=-1\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-3)+\sqrt{49}}{2(2)}=\frac{3+7}{4}=\frac{10}{4}=2,5$