Question

Determine as raizes da equação -2x²+4×+6=0

Answer 1

Resposta:

Explicação passo-a-passo:

-2x²+4×+6=0

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~-2x^{2}+4x+6=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=-2{;}~b=4~e~c=6\\\\\Delta=(b)^{2}-4(a)(c)=(4)^{2}-4(-2)(6)=16-(-48)=64\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(4)-\sqrt{64}}{2(-2)}=\frac{-4-8}{-4}=\frac{-12}{-4}=3\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(4)+\sqrt{64}}{2(-2)}=\frac{-4+8}{-4}=\frac{4}{-4}=-1\\\\S=\{3,~-1\}$