Question

determine as raízes dá equação ײ-8×+12=0

Answer 1

x² - 8x + 12 = 0
a = 1; b = - 8; c = 12

Δ = b² - 4ac
Δ = (-8)² - 4.1.12
Δ = 64 - 48
Δ = 16

x = - b +/- √Δ   =  - (-8) +/- √16
      ---------------    -------------------
            2a                   2.1

x = 8 + 4
      --------  = 12/2 = 6
          2

x = 8 - 4
      --------  = 4/2 = 2
         2

R.: x = 6 e x = 2

Answer 2

D=(-8)²-4.1.12
D=64-48
D=16

X=8±raiz de 16/2.1
X=8±4/2
X=8+4/2
X=12/2
X=6

X"=8-4/2
X"=4/2
X"=2

S={2,6}