Question

determine as raises das equações 2x elevado a 2 mais 6x = 0​

Answer 1

$\large\boxed{\begin{array}{l} \rm \: 2x {}^{2} + 6x = 0 \\ \\ \rightarrow \begin{cases} \rm \: a = 2 \\ \rm \: b = 6 \\ \rm \: c = 0\end{cases} \\ \\ \rm\Delta = b {}^{2} - 4ac \\ \Delta = 6 {}^{2} - 4 \: . \: 2 \: . \: 0 \\ \Delta = 36 - 0 \\\Delta = 36 \\ \\ \rm \: x = \dfrac{ - b \pm \sqrt{\Delta} }{2a} \\ \\ \rm \: x = \dfrac{ - 6 \pm \sqrt{36} }{2 \: . \: 2} \\ \\ \rm \: x = \dfrac{ - 6 \pm6}{4} \begin{cases} \rm \: x_1 = \dfrac{ - 6 + 6}{4} = \dfrac{0}{4} = \boxed{0} \\ \\ \rm \: x_2 = \dfrac{ - 6 - 6}{4} = \dfrac{ - 12}{4} = \boxed{ - 3} \end{cases}\end{array}}$