Question

determine as medidas das incógnitas utilizando as relações métricas​. pfff preciso p agora​

Answer 1

a)

${6}^{2} = 12x \\ x = \frac{36}{12} = 3$

${y}^{2} = 15x \\ y = \sqrt{15.3} = \sqrt{45} \\ y = \sqrt{9.5} = 3\sqrt{5}$

${z}^{2} = 15.12 \\ z = \sqrt{15.12} \\ z = \sqrt{3.5.3.4 } = \sqrt{9.4.5} = 6 \sqrt{5}$

b)

${x}^{2} = 3.9 \\ x = \sqrt{3.9} = 3 \sqrt{3}$

${y}^{2} = 12. 3 \\ y = \sqrt{12.3} = \sqrt{36} = 6$

${z}^{2} = 12.9 \\ z = \sqrt{12.9} = \sqrt{3.4.9} = 6 \sqrt{3}$

c)

${y}^{2} = 2.4 \\ y = \sqrt{2.4} = 2 \sqrt{2}$

${z}^{2} = 4.2 \\ z = \sqrt{4.2} = 2 \sqrt{2}$

${x}^{2} = 6.2 \\ x = \sqrt{6.2} = \sqrt{3.2.2} = \sqrt{3.4} \\ x= 2 \sqrt{3}$

d)

${(2 \sqrt{18} )}^{2} = 3.(y + 3) \\ y + 3 = \frac{72}{3 } \\ y + 3 = 24 \\ y = 24 - 3 \\ y = 21$

${x}^{2} = 24.21 \\ x = \sqrt{24.21} = \sqrt{4.2.3.3.7} \\ x = \sqrt{4.9.14} = 6 \sqrt{14}$

${z}^{2} = 21.3 \\ z = \sqrt{21.3} = \sqrt{7.3.3} = \sqrt{7.9} \\ z = 3 \sqrt{7}$

e)

${6}^{2} = 10x \\ x = \frac{36}{10} \\ x= 3,6$

$10y = 6.8 \\ y = \frac{48}{10} \\ y = 4,8$

$z = 10 - x = 10 - 3,6 = 6,4$