Question

Determine as medidas BC e AC da figura abaixo

Answer 1

Sem 60° = y / 8
√3 / 2 = y / 8
2y = 8√3
y = 8√3 / 2
y =4√3

( 8 ) 2 = ( 4√3 ) 2 + x2
64 = 48 + x2
x2 = 64 - 48
x2 = 16
x = √16
x = 4

TAG 45 = 4√3 / w
1 = 4√3 / w
W = 4√3

BC =4 + 4√3
BC = 4 ( 1 + √3)

( ac)2 = ( 4√3 ) 2 + ( 4√3 ) 2
( AC )2 = 48 + 48
( AC ) 2 = 96
AC = √96
AC = 4√6