Question

determine as coordenadas do vertice em cada caso.
f(x)= 2x²+4x+3
f(x) -x²+x-2

Answer 1

f(x)= 2x²+4x+3

a = 2   b = 4  c = 3

Δ= 4² - 4 . 2 . 3

Δ= 16 - 24

Δ = -8

vertices

XV = - b / 2.a

Xv = -4 / 2.2

XV = -4/ 4

Xv = -1

Yv = - (-8)/4.2

Yv = 8 / 8

Yv = 1

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f(x) -x²+x-2

a = - 1   b = 1   c = -2

Δ = 1² - 4 . (-1) . (-2)

Δ = 1 - 8

Δ = -7

XV = -b /2a

Xv =  - 1/2.(-1)

Xv = - 1/ -2

Yv = -Δ / 4.a

Yv = - (-7)/4.(-2)

Yv =  7 / -8