Question

Determine as coordenadas do vertice da parábola y=-x^2+2x+3

Answer 1

Vamos lá...

Xv = -b/2a
Xv = -2/-2
Xv = 1

Yv = -1² + 2 + 3
Yv = 4

V ( 1, 4)

Answer 2

y=-x^2+2x+3

y=-(x²-2x-3)

y=-(x²-2x+1-1-3)

y=-(x-1)²+4

y-4= -(x-1)² vx=1 e vy=4 ...vértice=(1,4)