Question

Determine as coordenadas do vértice da parábola da função j(x) = -2x²+8x-6.​

Answer 1

$\boxed{\begin{array}{l}\sf f(x)=-2x^2+8x-6\\\sf\Delta=b^2-4ac\\\sf\Delta=8^2-4\cdot(-2)\cdot(-6)\\\sf\Delta=64-48\\\sf\Delta=16\\\sf x_V=-\dfrac{b}{2a}\\\\\sf x_V=-\dfrac{8}{2\cdot(-2)}=\dfrac{8}{4}=2\\\\\sf y_V=-\dfrac{\Delta}{4a}\\\\\sf y_V=-\dfrac{16}{4\cdot(-2)}=\dfrac{16}{8}=2\\\sf V(2,2)\end{array}}$