Question

determine as coordenadas do vértice da função y = x² - 4

Answer 1

xv=-b/2a
xv=-0/2(1)
xv=-0/2
xv=0

yv= -Δ/4a
yv=-(b²-4ac)/4a
yv=-(0²-4.1.(-4)) / 4.1
yv= -(16)/4
yv=-4

Portanto as coordenadas do vértice são ( 0 , -4) 

Answer 2

$f(x)=x^{2}-4 \\ \\ Xv= \frac{-b}{2a} \\ Xv=\frac{-0}{2.1} \\ Xv=\frac{0}{2} \\ \boxed {Xv=0}$

$Yv= \frac{- \Delta}{4a} \\ Yv= \frac{- (b^{2}-4.a.c)}{4.1} \\ Yv= \frac{- (0^{2}-4.1.(-4)}{4} \\ Yv= \frac{-16}{4} \\ \boxed {Yv=-4}$

$Coordenadas: (0,-4)$