Question

Determine as coordenadas do vértice da função f(x)=4x²-40x+80.

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{f(x) = 4x^2 - 40x + 80}$

$\mathsf{\Delta = b^2 - 4.a.c}$

$\mathsf{\Delta = (-40)^2 - 4.4.80}$

$\mathsf{\Delta = 1.600 - 1.280}$

$\mathsf{\Delta = 320}$

$\mathsf{y_V = -\dfrac{\Delta}{4a} = \dfrac{-320}{16}}$

$\mathsf{y_V = -20}$

$\mathsf{x_V = -\dfrac{b}{2a} = \dfrac{40}{8}}$

$\mathsf{x_V = 5}$

$\boxed{\boxed{\mathsf{V(5;-20)}}}$