Question

determine a vertice da parabola que representa a funçao quadratica f(x)=x2-4x+3

Answer 1

x²-4x+3
a = 1
b = -4
c = 3

y do vertice = yv
formula do yv = -Δ/4*a
Δ  = b²-4*a*c
Δ = 16*1*3
Δ = 48
yv = -48/4*1
yv = -48/4
yv = -12

x do vértice = xv
formula do xv = -b/2*a
xv = -(-4)/2*1
xv = 4/2
xv = 2