Question

Determine a soma:
Dos termos da PG (2,4,...,2^10)

Me ajudem!

Answer 1

P.G.(2,4,....1024)q = a 2/a 1
q = 4/2
q = 2
a n = a 1 . q^n - 1
1024 = 2 . 2^n - 1
1024/2 = 2 ^n - 1
512 = 2 ^n - 1
2^9 = 2^n - 1
n - 1 = 9
n = 9 + 1
n = 10
S 10 = 1024 . 2 - 2 / 2 - 1
S 10 = 2048  - 2  /  1
S 10 = 2046 / 1
S 10 = 2046