Question

determine a soma dos termos da pg (1,3,9,...729)

Answer 1

an = a1.qⁿ⁻¹

729 = 1.3ⁿ⁻¹

729 = 1.3ⁿ⁻¹

3⁶ = 3ⁿ⁻¹

6 = n - 1

n = 7

 

Sn = a1(qⁿ - 1)/(q-1)

Sn = 1(3⁷ - 1)/(3-1)

Sn = (2187 - 1)/2

Sn = 2186)/2

Sn = 1093

Espero ter ajudado!

Answer 2

An = 729

a₁ = 1

q = a₂ / a₁

q = 3/1

q = 3

n = ?

An = a₁ * qⁿ⁻¹

729 = 1 * 3ⁿ⁻¹

3ⁿ⁻¹ = 729 / 1

3ⁿ⁻¹ = 729

3ⁿ⁻¹ = 3⁶

n - 1 = 6

n = 1 + 6  

n = 7

Sn = a₁ * (qⁿ - 1) / q - 1

S₇ = 1 * (3⁷ - 1) / 3 - 1

S₇ = 2187 - 1 / 2

S₇ = 2186 / 2

S₇ = 1 093