Question

determine a soma dos 8primeiros teremos de cada pg(-48-16)​

Answer 1

Resposta:

a1=-48

a2=-16

q=a2/a1=-16/(-48)=1/3

Sn=a1*(1-q^n)/(1-q)

Sn=-48 * [1-(1/3)⁸]/(1-1/3)

Sn=-48*(1-1/3⁸)/(2/3)

Sn=-24*(3-1/3⁷) =24/3⁷ - 72