Question

Determine a solução em cada uma das equaçoes a seguir
a)y+2/4-y-2/6=2/3+y
b)1/5-2(x+1)=2(x+3)/10-x

Answer 1

Letra A) $y+\frac{2}{4}-y- \frac{2}{6}= \frac{2}{3}+y \\\\ \frac{6-4}{12}-y=\frac{2}{3}+y-y\\\\ \frac{2}{12}-y=\frac{2}{3}\\\\ \frac{2}{12}-\frac{2}{3}=y\\\\ \frac{2-8}{12}=y\\\\ y=\frac{-6}{12}\\\\ y=\frac{-1}{2}$

Letra B) $\frac{1}{5}-2(x+1)=\frac{2(x+3)}{10}-x\\\\ \frac{1}{5}-2x-2=\frac{2x+6}{10}-x\\\\ \frac{1}{5}-2-\frac{6}{10}=\frac{2x}{10}-x+2x\\\\ \frac{2-6}{10}-2=\frac{2x}{10}+x\\\\ \frac{-4-20}{10}=\frac{2x+10x}{10}\\\\ \frac{-24}{10}=\frac{12x}{10}\\\\ 120x=-240\\\\ x=\frac{-240}{120}\\\\ x=-2$