Question

determine a resolucao da equacao x-1=x+3 sob x-3

Answer 1

$x-1=\dfrac{x+3}{x-3}\\\\ (x-3)(x-1)=x+3\\\\ x^2-x-3x+3=x+3\\\\ x^2-4x+3=x+3\\\\ x^2-4x-x+3-3=x+3\\\\ x^2-5x=0\\\\ x(x-5)=0\\\\ \boxed{x'=0}\\\\ x-5=0\\\\ \boxed{x''=5}$

Temos 2 valores que conseguem resolver a equação:
x = 0   e    x = 5

Apresentando prova real para x = 0:

$x-1=\dfrac{x+3}{x-3}\\\\ 0-1=\dfrac{0+3}{0-3}\\\\ -1=\dfrac{+3}{-3}\\\\ \boxed{-1=-1}$

Apresentando prova real para x = 5:

$x-1=\dfrac{x+3}{x-3}\\\\ 5-1=\dfrac{5+3}{5-3}\\\\ 4=\dfrac{8}{2}\\\\ \boxed{4=4}$

Espero ter ajudado.
Bons estudos!