Question

determine a razão de cada PG.

a) (3,12,48,.....)
b) (10,5,.....)
c) (5,-15,...)
d) (10,50,....)
​

Answer 1

Resposta:

1)

a)

$(3,12,48,...) \\ \\ q =\dfrac{12 }{3} \\ \\ \Large \: \boxed{ \green{ \bf \: q = 4}}$

b)

$(10,5,...) \\ \\ q = \dfrac{5÷5} { 10÷5}\\ \\ \Large \boxed{ \green{\bf q = \dfrac{ 1}{2}}}$

c)

$(5, - 15,...) \\ \\ q =\dfrac{ - 15}{ 5 }\\ \\ \Large \boxed{ \green{ \bf q = - 3}}$

d)

$(10,50,...) \\ \\ q = \dfrac{50}{ 10} \\ \\ \Large \boxed{ \green{ \bf q = 5}}$

e)

$( \sqrt{5} ,5,...) \\ \\ q =\dfrac{ 5}{ \sqrt{5}}×\dfrac{\sqrt{5}}{\sqrt{5}}\\\\ q = \dfrac{5\sqrt{5}}{\sqrt{25}} \\\\ q = \dfrac{5\sqrt{5}}{5}\\\\ \Large \boxed{\bf \green{q = \sqrt{5} }}$

f)

$(2,{2}^{6},...) \\ \\ q = \dfrac{ {2}^{6} }{ 2} \\ \\ q = {2}^{6-1} \\ \\ \Large \boxed{ \green{ \bf q =2^5 }} \\ \\ \Large \boxed{ \underline{ \blue{ \bf \: Bons \: Estudos!} \: 15/05/2021}}$