Question

Determine a razão da P.G. (-12, -3, -0,75)

Answer 1

$q=\dfrac{a_n}{a_{n-1}},\ para\ n\ge2,\ n\in\mathbb{N}\\\\\\q=\dfrac{a_2}{a_{2-1}}\\\\\\q=\dfrac{a_2}{a_{1}}\\\\\\q=\dfrac{-3}{-12}\\\\\\q=\dfrac{1}{4}$



A razão da P.G. é um quarto.

Answer 2

razão da P.G.

$a_2\div a_1=a_3 \div a_2 \\ \\ (-3)\div(-12)=(-0.75)\div(-3) \\ \\ (0,25)=(0,25) \\ \\ 0,25= \frac{25}{100} = \frac{1}{4 }$

razão da P.G.=$\frac{1}{4} ~~ou~~0,25$