Question

Determine a raiz das equações:

y + 4 (y -1) = 9 - 2 ( y +3)

4 (y-2) + 3 (2y - 1 = 6 (2y - 3 )

Answer 1

y+4(y-1) = 9-2(y+3)
y+4y-4=9-2y-6
5y+2y=3+4
7y=7
y=7/7
y=1


4(y-2)+3(2y-1)=6(2y-3)
4y-8+6y-3=12y-18
10y-12y= -18+11
-2y=-7(.-1)
2y=7
y=7/2

Answer 2

y + 4 (y -1) = 9 - 2 ( y +3)

y + 4y - 4 = 9 - 2y - 6 ==> y+4y+2y = 9-6+4

7y = 7 ==> y = 1
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4 (y-2) + 3 (2y - 1 = 6 (2y - 3 )

4y- 8 + 6y - 3 = 12y - 18 ==> 4y+ 6y - 12y = - 18 + 3 + 8

- 2y = - 7(-1) ==> 2y = 7 

y = 7/2