Question

determine a raiz da seguinte equação. X³-6X²+5x=0​

Answer 1

X³-6X²+5X=0

X³-X²+X=6-5

X=1

Answer 2

x3-6x2+5x=0

X(x2-6x+5)

delta

Δ=b2-4ac

=(-6)2-4*1*5

=36-4*1*5

=16

X1/2=-b±√Δ/2a

X1/2=-(-6)±√16/2*1

X1/2=6±4/2

X1=6+4/2=10/2=5

X2=6-4/2=2/2=1