Question

Determine a natureza do triângulo A (2,-3) B ( -5,1) C (4,3)

Answer 1

A(2,-3) B =(-5,1)

d(AB) = √(xb-xa)² + (yb-ya)²

d(AB) = √(-5-2)² + (1-(-3))²

d(AB) = √(-7)² + (1+3)²

d(AB) = √49 + (4)²

d(AB) = √49 + 16

d(AB) = √65

B(-5,1) C(4,3)

d(BC) = √(xc-xb)² + (yc-yb)²

d(BC) = √(4-(-5))² + (3-1)²

d(BC) = √(4+5)² + (2)²

d(BC) = √(9)² + 4

d(BC) = √81 + 4

d(BC) = √85

C(4,3) A(2,-3)

d(AC) = √(xc-xa)² + (yc-ya)²

d(AC) = √(4-2)² + (-3-3)²

d(AC) = √(2)² + (-6)²

d(AC) = √4 + 36

d(AC) = √40

Triângulo Escaleno, pois possui todos os lados diferentes.

Espero ter ajudado

Bons estudos ♥️