Question

Determine a medida no triângulo ABC ​

Answer 1

Pela lei dos senos

$\frac{12}{ \sin( \alpha ) } = \frac{12 \sqrt{2} }{ \sin(45) } \\ \frac{1}{ \sin( \alpha ) } = \frac{ \sqrt{2} }{ \frac{ \sqrt{2} }{2} }$

$\frac{1}{ \sin( \alpha ) } = \sqrt{2} . \frac{2}{ \sqrt{2} } \\ \frac{1}{ \sin( \alpha ) } = 2 \\ \sin( \alpha ) = \frac{1}{2}$

$\alpha = arc \sin( \frac{1}{2} ) = 30$