Determine a medida do raio da circunferência circunscrita a um triângulo ABC, sendo BC = 15cm e m (Â) =30graus
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Boa tarde Carla!
Solução!
Para resolver esse exercício,basta aplicar a lei dos senos.
![\dfrac{a}{Sen\widehat{A}}= \dfrac{b}{Sem\widehat{B}}= \dfrac{c}{Sem\widehat{C}}=2r\\\\\\\ a=15\\\\\\\
Sen(A)=30\º= \dfrac{ 1 }{2}\\\\\\\\\\\\
\frac{15}{ \dfrac{1}{2} }=2r\\\\\\\
15= \frac{1}{2}.2r\\\\\\
15=r\\\\\
\boxed{r=15}](https://tex.z-dn.net/?f=+%5Cdfrac%7Ba%7D%7BSen%5Cwidehat%7BA%7D%7D%3D+%5Cdfrac%7Bb%7D%7BSem%5Cwidehat%7BB%7D%7D%3D++%5Cdfrac%7Bc%7D%7BSem%5Cwidehat%7BC%7D%7D%3D2r%5C%5C%5C%5C%5C%5C%5C+a%3D15%5C%5C%5C%5C%5C%5C%5C%0ASen%28A%29%3D30%5C%C2%BA%3D+%5Cdfrac%7B+1+%7D%7B2%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A+%5Cfrac%7B15%7D%7B+%5Cdfrac%7B1%7D%7B2%7D+%7D%3D2r%5C%5C%5C%5C%5C%5C%5C%0A15%3D+%5Cfrac%7B1%7D%7B2%7D.2r%5C%5C%5C%5C%5C%5C%0A15%3Dr%5C%5C%5C%5C%5C%0A%5Cboxed%7Br%3D15%7D++++++ "\dfrac{a}{Sen\widehat{A}}= \dfrac{b}{Sem\widehat{B}}= \dfrac{c}{Sem\widehat{C}}=2r\\\\\\\ a=15\\\\\\\
Sen(A)=30\º= \dfrac{ 1 }{2}\\\\\\\\\\\\
\frac{15}{ \dfrac{1}{2} }=2r\\\\\\\
15= \frac{1}{2}.2r\\\\\\
15=r\\\\\
\boxed{r=15}")
Boa tarde!
Bons estudos!
Solução!
Para resolver esse exercício,basta aplicar a lei dos senos.
Boa tarde!
Bons estudos!
carlaSilveira:
Obrigado
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