Question

determine a medida do ad no triângulo a seguir​

Answer 1

Resposta:

Explicação passo-a-passo:

AD = DB

$sen60=\frac{12}{DB}\\\frac{\sqrt{3}}{2}=\frac{12}{DB}\\\\DB\sqrt{3}=24\\DB=\frac{24}{\sqrt{3}}$

$DB=\frac{24}{\sqrt{3}}*\frac{\sqrt{3}}{\sqrt{3}}=\frac{24\sqrt{3}}{3}\\DB=8\sqrt{3}\\AD=8\sqrt{3}$