Question

Determine a medida de x no triângulo dado. 
ME AJUDEM POR FAVOR​

Answer 1

$\boxed{\begin{array}{l}\sf x^2+32^2=40^2\\\sf x^2+(8\cdot4)^2=(8\cdot5)^2\\\sf x^2=(8\cdot5)^2-(8\cdot4)^2\\\sf x^2=[8\cdot5+8\cdot4]\cdot[8\cdot 5-8\cdot 4]\\\sf x^2=8\cdot[5+4]\cdot 8[5-4]\\\sf x^2=8^2\cdot9\cdot 1\\\sf x^2=8^2\cdot 3^2\\\sf x=\sqrt{8^{\backslash\!\!\!2}\cdot3^{\backslash\!\!\!2}}\\\sf x=8\cdot 3\\\sf x=24\end{array}}$