Question

Determine a medida BC do triângulo abaixo;​

Answer 1

Resposta:

$\overline{BC}=6$

Explicação passo-a-passo:

Lei dos senos:

$\displaystyle \frac{6\sqrt{2}}{sen45^{\circ}} =\frac{\overline{BC}}{sen30^{\circ}} \\\\\\\overline{BC}=6\sqrt{2}.\frac{sen30^{\circ}}{sen45^{\circ}} =6\sqrt{2}.\frac{\frac{1}{2}}{\frac{\sqrt{2} }{2} } =6\diagup\!\!\!\!\!\!\sqrt{2}.\frac{1}{\diagup\!\!\!\! 2}.\frac{\diagup\!\!\!\! 2}{\diagup\!\!\!\!\!\! \sqrt{2}} =6$