Question

determine a matriz A2x3 sabendo que aij= -2ielevando a2+4j

Answer 1

$\begin{array}{l}\mathsf{A=(aij)_{2x3}=-2i^2+4j}\\\\\\\textsf{Onde i representa as linhas, e j as colunas.}\\\\\\\mathsf{a_{11}=(-2\cdot 1^2)+(4\cdot 1) = (-2\cdot 1)+4=-2+4=2}\\\\\mathsf{a_{21}=(-2\cdot 2^2)+(4\cdot 1)=(-2\cdot 4)+4=-8+4=-4}\\\\\mathsf{a_{12}=(-2\cdot 1^2)+(4\cdot 2)=(-2\cdot 1)+8=-2+8=6\\\\}\end{array}$

$\begin{array}{l}\mathsf{a_{22}=(-2\cdot 2^2)+(4\cdot 2)=(-2\cdot 4)+8=-8+8=0}\\\\\mathsf{a_{13}=(-2\cdot 1^2)+(4\cdot 3)=(-2\cdot 1) +12=-2+12=10}\\\\\mathsf{a_{23}=(-2\cdot 2^2)+(4\cdot 3)=(-2\cdot 4)+12=-8+12=4}\end{array}$


$\textsf{Substituindo os dados na matriz:}$



$\large A=\begin{pmatrix} a_{11} &a_{12} &a_{13} \\ a_{21} &a_{22} &a_{23} \end{pmatrix}$



$\large~A=\begin{pmatrix} 2 & 6 & 10\\ -4 & 0 & 4 \end{pmatrix}$