Question

Determine a matriz A = (aij)3x3 tal que
aij = i–j.

Answer 1

A= ( a11 a12 a13 ) ( a21 a22 a23) ( a31 a32 a33 ) A= I-J ( 1-1= 0 ),(1-2= -1),(1-3= -2) (2-1= 1), (2-2= 0), (2-3= -1) (3-1= 2), (3-2= 1), (3-3= 0) A= ( 0 -1 - 2) (1 0 -1) (2 1 0 )

Answer 2

A = (aij) 3x3, sendo aij = i-j

$A= \left[\begin{array}{ccc}a_{11}&a_{12}&a_{13}\\a_{21}&a_{22}&a_{23}\\a_{31}&a_{32}&a_{33}\end{array}\right]$

$a_{11}=1-1=0 \\ a_{12}=1-2=-1 \\ a_{13}=1-3=-2 \\ a_{21}=2-1=1 \\ a_{22}=2-2=0 \\ a_{23}=2-3=-1 \\ a_{31}=3-1=2 \\ a_{32}=3-2=1 \\ a_{33}=3-3=0$

$A= \left[\begin{array}{ccc}0&-1&-2\\1&0&-1\\2&1&0\end{array}\right]$