Question

Determine a matriz A= (aij) 2×3, tal que aij = 2i - j

Answer 1

$\left[\begin{array}{ccc}a11&a12&a13\\a21&a22&a23\\\end{array}\right]$

a11 = 2 × 1 - 1 → 2 - 1 = 1

a12 = 2 × 1 - 2 → 2 - 2 = 0

a13 = 2 × 1 - 3 → 2 - 3 = -1

a21 = 2 × 2 - 1 → 4 - 1 = 3

a22 = 2 × 2 - 2 → 4 - 2 = 2

a23 = 2 × 2 - 3 → 4 - 3 = 1

$A= \left[\begin{array}{ccc}1&0&-1\\3&2&1\\\end{array}\right]$