Question

Determine a intensidade da força eletrica entre Q1 12,0 Nc e q2 5,0 pc

Answer 1

Dados:

q1=12 nC=12•10^-9

q2=5 pC= 5•10^-12

k=9•10^9

F=?


F=k.q1.q2/d^2

F=9•10^9 * 12•10^-9 * 5•10^-12/d^2

F=540•10^-12/d^2

F=5,4•10^-10/d^2



Moçambique (ing. Mecânico)