Question

Determine a integral indefinida de F(x) detalhes na foto (cálculo)

Answer 1

Resposta:

Letra A

Explicação passo a passo:

$\displaystyle\int \frac{senx}{\sqrt{2-cosx} }dx=?\\\\2-cosx=u\impliessenxdx\implies senx=du\\\\\displaystyle\int \frac{senx}{\sqrt{2-cosx} }dx=\displaystyle\int \frac{du}{\sqrt{u} } =\displaystyle\int \frac{du}{u^{\frac{1}{2} } }=\displaystyle\int u^{-\frac{1}{2} } du} =u\frac{\frac{1}{2} }{\frac{1}{2} }+c =2\sqrt{u} +c=\\\\\\2\sqrt{2-cosx}+c$