Question

determine a fração geratriz periódica de 1,234343

Answer 1

$x=1,234343....$.

$(x=1,234343....).10$ =>
$10x=12,34343....)$.

$(x=1,234343....).1000$ =>
$1000x=1234,34343...$.

$\left \{ {{1000x=1234,34343...} \atop {10x=12,34343....}} \right.$

Subtração:

$990x=1222$ =>
$x=\frac{1222}{990}$ =>
$x=\frac{611}{495}$.