Determine a fração geratriz das dízimas a seguir: a) 1,333... b)0,583333... c)0,4090909...
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A) x = 1,333 10x = 13,333
10x - x = 13,333 - 1,333
9x = 12
x = 12/9 >>>4/3
b) x = 0,58333 100x = 58,333 1000x = 583,333
1000x - 100x = 583,333 - 58,333
900x = 525
x = 525/900 >>>7/12
C) x = 0,409090 10x = 4,0909 1000x = 409,0909
1000x - 10x = 409,0909 - 4,0909
990x = 405
x = 405/990 >>>9/22
10x - x = 13,333 - 1,333
9x = 12
x = 12/9 >>>4/3
b) x = 0,58333 100x = 58,333 1000x = 583,333
1000x - 100x = 583,333 - 58,333
900x = 525
x = 525/900 >>>7/12
C) x = 0,409090 10x = 4,0909 1000x = 409,0909
1000x - 10x = 409,0909 - 4,0909
990x = 405
x = 405/990 >>>9/22
Ruam007:
vc poderia me explicar a c ?
O que vc n entendeu?
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