Question

determine a expressão
$sen330 - cos240 - sen120 \\\ sen270 + cos180$
​

Answer 1

sen330=-sen30=-1/2

cos240=-cos60=-1/2

sen120=sen60=√3/2

sen270=-1

cos180=-1

-1/2-(-1/2)-√3/2/-1-1

-√3/2/-2

√3 //.