Question

Determine a equação:
Pi^x^2-5x=1

Answer 1

$\pi ^{x^2-5x} =1$

$\pi ^{x^2-5x} = \pi ^0$

Cancelando as bases que são iguais temos: 
x²-5x=0
a=1
b=-5
c=0
Bhaskara 

Δ=b²-4ac
Δ=5²+4.1.0
Δ=25

x=(-b+-√Δ)/2a

x=(5+-√25)/2

x=5+-5/2

x'=10/2= 5

x''=0/2=0


$\left[\begin{array}{ccc}\\S={(0,5})\\\end{array}\right]$