Question

determine a equação geral da reta q passa pelo ponto A(-1,0) e B(3,2).​

Answer 1

$\Large\boxed{\begin{array}{l}\sf\begin{vmatrix}\sf-1&\sf0&\sf1\\\sf3&\sf2&\sf1\\\sf x&\sf y&\sf 1\end{vmatrix}=0\\\sf -1\cdot(2-y)+1\cdot(3y-2x)=0\\\sf -2+y+3y-2x=0\\\sf -2x+4y-2=0\div(-2)\\\sf x-2y+1=0\end{array}}$

Answer 2

Resposta:

x - 2y + 1 = 0

Explicação passo a passo:

$\left|\begin{array}{cccc}x&-1&3&x\\y&0&2&y\end{array}\right|_{+}^{-}=0\\\\|x.0-1.2+3.y-y(-1)-0.3-2.x|=0\\\\|0-2+3y+y-0-2x|=0\\\\|-2x+4y-2|=0\\\\-2x+4y-2=0\\Dividir~ por -2\\\\x-2y+1=0$