Question

Determine A equação da reta que passa pelos pontos:
A (4,6) e B (8,10)

Answer 1

$\large\mathsf{\begin{vmatrix}4&6&1\\8&10&1\\x&y&1\end{vmatrix}=0}$

$\mathsf{4(10-y)-6(8-x)+1(8y-10x)=0}\\\mathsf{40-4y-48+6x+8y-10x=0}\\\mathsf{-4x+4y-8=0\div(-4)}$

$\boxed{\boxed{\mathsf{x-y+2=0}}}$