Question

Determine a energia potencial gravitacional de um passaro de 2 kg que voa a altura de 300 m do solo.Considere g=10 m/s2

Answer 1

$\Large\displaystyle\text{ \begin{gathered} \hookrightarrow\boxed{ \boxed{ { \bf{ E_{Pg} = 6000~J }}}} \end{gathered} }$

• Explicação:

$\Large\displaystyle\text{ \begin{gathered} \sf{ E_{Pg} = m \cdot g \cdot h } \end{gathered} }$

Epg⇒energia potencial gravitacional (J)

m⇒massa do corpo (kg)

g⇒aceleração da gravidade (m/s²)

h⇒altura (m)

$\Large\displaystyle\text{ \begin{gathered} \sf{ E_{Pg} = m \cdot g \cdot h } \end{gathered} }$

$\Large\displaystyle\text{ \begin{gathered} \sf{ E_{Pg} = 2\cdot10 \cdot300 } \end{gathered} }$

$\Large\displaystyle\text{ \begin{gathered} \boxed{ \boxed{\sf{ E_{Pg} = 6000 \:J }} } \end{gathered} }$