Question

Determine " A " e " B " no triângulo abaixo

Answer 1

$A)$
$cos47= \frac{CATETO ADJACENTE}{HIPOTENUSA} \\ 0,6820= \frac{17}{a} \\ a= \frac{17}{6820} \\ a= 24,92 \\ \\ sen47= \frac{CATETO OPOSTO}{HIPOTENUSA} \\ 0,7314= \frac{b}{24,92} \\ b= 0,7314 .24,92 \\ b=18,2$

$B)$
$sen23= \frac{b}{13,7} \\ 0,3907= \frac{b}{13,7} \\ b=13,7.0,3907 \\ b= 5,35 \\ \\ tg23= \frac{CATETO OPOSTO}{CATETO ADJACENTE} \\ \\ 0,4245= \frac{5,35}{a} \\ \\ a= \frac{5,35}{0,4245} \\ \\ a=12,6$