Question

DETERMINE A DISTÂNCIA "BC"
b (2,1) c (4,1) ​

Answer 1

Resposta:

$2$

Explicação passo-a-passo:

$d = \sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2} }$

$d = \sqrt{(4 - 2) {}^{2} + (1 - 1) {}^{2} } = \sqrt{2 {}^{2} - 0 {}^{2} } = \sqrt{2 {}^{2} } = \sqrt{4} = 2$

Answer 2

$\sf B(2,1)\quad C(4,1)$

$\sf d_{BC}=\sqrt{(x_C-x_B)^2+(y_C-y_B)^2}$

$\sf d_{BC}=\sqrt{(4-2)^2+(1-1)^2}$

$\sf d_{BC}=\sqrt{(2)^2+(0)^2 }$

$\sf d_{BC}=\sqrt{4+0}$

$\sf d_{BC}=\sqrt{4}$

$\red{\sf d_{BC}=2}$