Question

Determine a área total e o volume de um tetraedro regular cuja aresta mede 4m.

Answer 1

Área:

At = a²√3

At = 4² · √3

At ≈ 27,71 m²
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Volume:

$V= \dfrac{a^3 \sqrt{2} }{12} \\\\\\\\\\V= \dfrac{4^3 \sqrt{2} }{12} \\\\\\\\V= \dfrac{64 \sqrt{2} }{12} \\\\\\ V=\dfrac{90,5}{12} \\\\\\V \approx 7,54\ m^3$


Forte abraço!