Determinar os valores de M e N para que os vetores u=(M+1, 3, 1) e v=(4, 2, 2N-1) sejam paralelos.
P.S=Se puder fazer passo a passo :)
#Obrigada
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Bom dia Ana!
Solução!
Vamos organizar os dados.

Fazendo agora.



Vamos igualar os vetores.



Veja que na segunda coordenada já podemos determinar o valor de W,e facilmente determinar os valores de M e N.


















Bom dia!
Bons estudos!
Solução!
Vamos organizar os dados.
Fazendo agora.
Vamos igualar os vetores.
Veja que na segunda coordenada já podemos determinar o valor de W,e facilmente determinar os valores de M e N.
Bom dia!
Bons estudos!
Anahofficial:
Muiito Obrigada !!! ;-)
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