Question

Determinar os cincos primeiros termos da sequencia dadas por:
A) an=3n+1
B) an=3n-4
C) an=2n-2
D) an=2.n²
E) an=5n
F) an=6n²

Answer 1

Explicação passo-a-passo:

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a)

$\boxed{a_{n} =3n+1}\\\\a_{1} =3.1+1=3+1=4\\a_{2} =3.2+1=6+1=7\\a_{3} =3.3+1=9+1=10\\a_{4} =3.4+1=12+1=13\\a_{5} =3.5+1=15+1=16$

b)

$\boxed{a_{n} =3n-4}\\\\a_{1} =3.1-4=3-4=-1\\a_{2} =3.2-4=6-4=2\\a_{3} =3.3-4=9-4=5\\a_{4} =3.4-4=12-4=8\\a_{5} =3.5-4=15-4=11$

c)

$\boxed{a_{n} =2n-2}\\\\a_{1} =2.1-2=2-2=0\\a_{2} =2.2-2=4-2=2\\a_{3} =2.3-2=6-2=4\\a_{4} =2.4-2=8-2=6\\a_{5} =2.5-2=10-2=8$

d)

$\boxed{a_{n} =2.n^{2} }\\\\a_{1} =2.1^{2}=2.1=2\\a_{2} =2.2^{2}=2.4=8\\a_{3} =2.3^{2}=2.9=18\\a_{4} =2.4^{2}=2.16=32\\a_{5} =2.5^{2}=2.25=50$

e)

$\boxed{a_{n} =5.n}\\\\a_{1} =5.1=5\\a_{2} =5.2=10\\a_{3} =5.3=15\\a_{4} =5.4=20\\a_{5} =5.5=25$

f)

$\boxed{a_{n} =6.n^{2} }\\\\a_{1} =6.1^{2}=6.1=6\\a_{2} =6.2^{2}=6.4=24\\a_{3} =6.3^{2}=6.9=54\\a_{4} =6.4^{2}=6.16=96\\a_{5} =6.5^{2}=6.25=150$